The period of oscillation of a simple pendulum of length (L) suspended from the roof of a vehicle which moves without friction down an inclined plane of inclination (prop), is given by.

Options

A. `2 pi sqrt((L)/((g cos alpha)))`
B. `2 pi sqrt((L)/((g sin alpha)))`
C. `2 pi sqrt((L)/(g))`
D. `2 pi sqrt((L)/((g tan alpha)))`

Answer

A

Explanation

`g_(e)=g-a`

where, a = acceleration of roof.
`|g_(e)|=g cos alpha`
`therefore" "T = 2pi sqrt((L)/(g cos alpha))`