Two pendulums have time period T and 5T/4. They starts SHM at the same time from the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation ?

Options

A. `45^(@)`
B. `90^(@)`
C. `60^(@)`
D. `30^(@)`

Answer

B

Explanation

`because` Phase difference, `Delta phi = (2pi)/(T).Delta t`
Here `Delta t=(5T)/(4)-T=(T)/(4)`
`therefore" "Delta phi = (2pi)/(T)(T)/(4)=(pi)/(2)`