A man measures time period of a pendulum (T) in stationary lift. If the lift moves upward with acceleration `(g)/(4)`, then new time period will be

Options

A. `T/2`
B. `T/4`
C. `sqrt(3)T//4`
D. `sqrt(3)T//2`

Answer

D

Explanation

As lift is moving upwards with acceleration g/3,
`g_(eff)=g + (g)/(3)=(4g)/(3)`
`T'=2pi sqrt((l)/(g_(eff)))=2pi sqrt((l)/(4g//3))`
`= (sqrt(3))/(2)(2pi sqrt((l)/(g)))=(sqrt(3))/(2)T`