A water drop is divided into 8 equal droplets. The pressure difference between the inner and outer side of the big drop will be

Options

A. same as for smaller droplet
B. `(1)/(2)` of that for smaller droplet
C. `(1)/(4)` of that for smaller droplet
D. twice that for smaller droplet

Answer

B

Explanation

Volume of big drop = Volume of 8 small droplets
i.e., `(4)/(3)pi R^(3) = 8 xx (4)/(3)pi R^(3) rArr r = (R)/(2)`
For smaller drop, `Delta p_(s) = (2S)/(r) = (2S)/(R//2) = (4S)/(R)`
For bigger drop, `Delta p_(b) = (2S)/(R) = (1)/(2)Delta p_(s)`