Two capillary tubes of same diameter are put vertically one each in two liquids whose relative densities are 0.8 and 0.6 and surface tensions are 60 dyne/cm and 50 dyne/cm respectively. Ratio of heights of liquids in the two tubes `(h_(1))/(h_(2))` is

Options

A. `(10)/(9)`
B. `(10)/(3)`
C. `(10)/(3)`
D. `(9)/(10)`

Answer

D

Explanation

`h = (2T cos theta)/(rdg)`
`:. (h_(1))/(h_(2)) = (T_(1))/(T_(2)) xx (d_(2))/(d_(1))`
`= (60)/(50) xx (0.6)/(0.8) = (9)/(10)`