Under a pressure head, the rate of orderly volume of liquid flowing through a capillary tube is Q. If the length of capaillary tube were doubled and diameter of the bore is halved, the rate of flow would become

Options

A. `(Q)/(4)`
B. 16 Q
C. `(Q)/(8)`
D. `(Q)/(32)`

Answer

D

Explanation

As, `Q = (pi p r^(4))/(8 eta l)` and `Q_(1) = (pi r(r//2)^(4))/(8 eta (2l)) = (Q)/(32)`