Wave of frequency 500 Hz has a phase velocity `360 m//s`. The phase difference between two displacement at a certain point at time `10^(-3)s` apart will be

Options

A. `pi` rad
B. `pi//2` rad
C. `pi//4` rad
D. `2 pi` rad

Answer

A

Explanation

Here, `n=500` Hz, `T=1/n=1/500=2 xx10^(-3) s`
Phase difference corresponding to `2xx10^(-3) s=2pi`
Phase difference corresponding to `1=10^(-3) s`
`=(2pi xx1xx10^(-3))/(2xx10^(-3))=pi` rad