The equation of a wave on a string of linear mass density `0.04 kg m^(-1)` is given by `y = 0.02 (m) sin [2pi((t)/(0.04(s))-(x)/(0.50(m)))]`. The tension in the string is :

Options

A. 4.0 N
B. 12.5 N
C. 0.5 N
D. 6.25 N

Answer

D

Explanation

Tension is the string is
`T=mu v^(2)=mu omega^(2)/k^(2)`
`=0.04 ((2pi//0.04)^(2))/((2pi//0.50)^(2))=6.25 N`