Two sitar strings A and B are slightly o...

Two sitar strings A and B are slightly out of tune and produce beats of frequency 5 Hz. When the tension in the string B is slightly increased, the beat frequency is found to reduce to 3 Hz. If the frequency of string A is 427 Hz, the original frequency of string B is

460 Hz

455 Hz

445 Hz

440 Hz

Text Solution

Verified by Experts

The correct Answer is:

`n_(A)=` known frequency `=450` Hz, `n_(B)=?, x=5` Hz which is decreasing after tension is increased (i.e. `x darr)
Hence, `n_(A)darr-n_(B)=x darr` ...(i) corect
`n_(B)-n_(A)=x darr` ...(ii) wrong
`implies n_(B)=n_(A)-x=450-5=445` Hz

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