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A string is hanging from a rigid support...

A string is hanging from a rigid support. A transverse
pulse is excited at its free end. The speed at which the
pulse travels a distance x is proportional to

A

x

B

`1/x`

C

`1/sqrt(x)`

D

`sqrt(x)`

Text Solution

Verified by Experts

The correct Answer is:
d
Speed of transverse pulse, `v=sqrt(T/mu)`
where, `mu` is mass of string per unit length.
For a transverse pulse, `T=muxg`
`therefore v=sqrt((muxg)/mu)rArr v prop sqrt(x)`
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