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A string has tension T. For tripling the...

A string has tension T. For tripling the frequency. The tension is string will become

A

3T

B

`T/9`

C

`T/sqrt(3)`

D

9T

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The correct Answer is:
To solve the problem of how the tension in a string must change to triple its frequency, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Relationship**: The frequency \( f \) of a string fixed at both ends is related to the tension \( T \) in the string by the formula: \[ f \propto \sqrt{T} \] This means that the frequency is proportional to the square root of the tension. 2. **Setting Initial Conditions**: Let the initial tension be \( T_1 = T \) and the initial frequency be \( f_1 \). Therefore, we can express the relationship as: \[ f_1 \propto \sqrt{T} \] 3. **New Frequency Condition**: We want to triple the frequency, so the new frequency \( f_2 \) will be: \[ f_2 = 3f_1 \] 4. **Expressing New Tension**: According to the proportionality, we can write: \[ f_2 \propto \sqrt{T_2} \] where \( T_2 \) is the new tension we need to find. 5. **Setting Up the Ratio**: Now, we can set up the ratio of the frequencies: \[ \frac{f_1}{f_2} = \frac{\sqrt{T_1}}{\sqrt{T_2}} \] Substituting \( f_2 = 3f_1 \): \[ \frac{f_1}{3f_1} = \frac{\sqrt{T}}{\sqrt{T_2}} \] This simplifies to: \[ \frac{1}{3} = \frac{\sqrt{T}}{\sqrt{T_2}} \] 6. **Squaring Both Sides**: To eliminate the square roots, we square both sides: \[ \left(\frac{1}{3}\right)^2 = \frac{T}{T_2} \] This gives us: \[ \frac{1}{9} = \frac{T}{T_2} \] 7. **Finding \( T_2 \)**: Rearranging the equation to solve for \( T_2 \): \[ T_2 = 9T \] ### Final Answer: Thus, to triple the frequency of the string, the tension in the string must become \( 9T \). ---

To solve the problem of how the tension in a string must change to triple its frequency, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Relationship**: The frequency \( f \) of a string fixed at both ends is related to the tension \( T \) in the string by the formula: \[ f \propto \sqrt{T} \] ...
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-STATIONARY WAVES -EXERCISE 1
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  18. A wave representing by the equation y = a cos(kx - omegat) is suerpose...

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  19. Two stratched strings of same material are vibrating under some tensio...

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