A stretched string of length l, fixed at both ends can sustain stationary waves of wavelength `lambda` given by

Options

A. `lambda = n^(2)/(2l)`
B. `lambda = l^(2)/(2n)`
C. `lambda = (2l)/(n)`
D. `lambda = 2ln`

Answer

c

Explanation

If number of loops in string is n, then, ltbtgt `l = (nlambda)/2rArr lambda = (2l)/n`