The temperature at which the speed of sound in air becomes double its value at `0^(@) C` is

Options

A. `1092^(@)`C
B. 819 K
C. `819^(@)`
D. `546^(@)`

Answer

c

Explanation

Speed, `v prop sqrt(T)`
`therefore (2v)/v=sqrt(T_(2)/T_(1))or 2=sqrt(T_(2)/T_(1))rArr 4 = T_(2)/T_(1)`
`T_(2)=4T_(1)=4xx273=1092 ` K
`rArr T_(2)=1092-273`
`=819^(@)`C