The frequency of the third overtone of a closed pipe
of length `L_(c)` is the same as the frequency of the sixth
overtone of an open pipe of the length `L_(o).` Then

Options

A. `L_(o)/L_(c)=4`
B. `L_(o)/L_(c)=2/1`
C. `L_(o)/L_(c)=1/4`
D. `L_(o)/L_(c)=1/2`

Answer

b

Explanation

For third overtone of closed pipe, the frequency
`=7n(7V)/(4L_(c))`
and for sixth overtone of the pipe `(L_(o) )7n'=(7V)/(2L_(o))`
`therefore (7V)/(4L_(o))=(7V)/(2L_(c)) therefore L_(o) /L_(c)=2/1`