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A pipe open at both produces a note of fundamental frequency `v_(1)` When the pipe is kept with `3/4` th of its length in water, it produces a note of fundamental frequency `v_(2)` The ratio of `v_(1)/v_(2)` is

A

`4/3`

B

`3/4`

C

2

D

`1//2`

Text Solution

Verified by Experts

The correct Answer is:
d
Accordingly `v_(1)=v/(2l)` ...(i)
and `v_(2)=v/(4l//4) = v/l` ...(ii)
Hence, `v_(1)/v_(2)=1/2`
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