If the end correction of an open pipe is 0.8 cm, then the inner radius of that pipe will be

Options

A. `1/3` cm
B. `2/3` cm
C. `3/2` cm
D. `0.2` cm

Answer

b

Explanation

For an open organ pipe, the relation between and
correction and inner radius of the organ pipe is given by `Delta l - 1.2 xxr`
[`Delta l= `end correction , r = inner radius]
So, `r=(Delta l )/1.2= (0.8)/1.2 [because Delta l = 0.8]`
`=2/3 cm`