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In a resonance tube the first resonance ...

In a resonance tube the first resonance with a tuning fork occurs at 16 cm and second at 49 cm . If the velocity of sound is 330 m/s , the frequency of tuning fork is

A

500

B

300

C

330

D

165

Text Solution

Verified by Experts

The correct Answer is:
a
For closed pipe `l_(1)=v/(4n) and l_(2)=(3l)/(4n)`
`v = 2n(l_(2)-l_(1)) rArr n = v/(2(l_(2)-l_(1)))`
`=330/(2xx (0.49-0.16))=500` Hz
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