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In a resonance pipe the first and second...

In a resonance pipe the first and second resonance are obtained at depths 22.7 cm and 70.2 respectively. What will be the end correction?

A

`1 .05` cm

B

`115.5` cm

C

`92.5` cm

D

`113. 5` cm

Text Solution

Verified by Experts

The correct Answer is:
a
For and correction `x, (l_(1)+x)/(l_(1)+ x ) = (3lambda //4)/(lambda//4) =3`
`rArr x= (l_(2)-3l_(1))/2=(70.2-3xx 22.7)/2`
` = 1.05` cm
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