Air is filled in a container of `333K.` Calculate the tempeture upto which it should be heated so that `1//3 rd of air may escope out of th vessel.

Options

A. 550 K
B. 400 K
C. 333 K
D. 444 K

Answer

D

Explanation

Given , `T_(1)=333K,T_(2)`=?
`V_(1)=V,V_(2)=V+(V)/(3)=(4)/(3)V`
According to charles 'law , we get
`(V_(2))/(V_(1))=(T_(2))/(T_(1))rArrT_(2)=T_(1)(V_(2))/(V_(1))=333xx(4)/(3)=444K`