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At a constant pressure of 10^(4)Nm^(-2)...

At a constant pressure of `10^(4)Nm^(-2)` , a gas expands by `0.25m^(3)` work done by the gas is

A

2500 J

B

250 J

C

25 J

D

2.5 J

Text Solution

Verified by Experts

The correct Answer is:
A
Given pressure , `p=10^(4)Nm^(-2)` , volume , `V=0.25m^(3)` , work done , W= ? ,
we know that , `W=pdV=10^(4)xx0.25`
=2500 J
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