A refrigerator transfers 250 J heat per second from `-23^(@)C` to `-25^(@)C` . Find the power consumed , assuming no loss of energy.

Options

A. `48 Js^(-1)`
B. `50 Js^(-1)`
C. `52 Js^(-1)`
D. `53 Js^(-1)`

Answer

A

Explanation

Here , `Q_(2)=250Js^(-1),T_(2)=-23+273=250K`
`T_(1)=25^(@)C=25+273=298K`
power = work per second
We know that , `beta=(Q_(2))/(W)=(T_(2))/(T_(1)-T_(2))=(250(298-250))/(250)`
`therefore W=(250xx48)/(250)=48Js^(-1)`