During an experiment, an ideal gas is found to obey an additional law `VP^2=constant,` The gas is initially at a temperature T, and volume V. When it expands to a volume `2V,` the temperature becomes…….

Options

A. `sqrt3T`
B. `sqrt(1//2T)`
C. `sqrt(2T)`
D. `sqrt(3T)`

Answer

C

Explanation

Here , it is given that `Vp^(2)` =Constant K(say). Hence, we may write the equation as , pV=nRT
`or " " sqrt((K)/(V)).V=nRT`
`or " " sqrt(V)=(nR)/sqrt(K)T`
`therefore" " sqrt((V_(1))/(V_(2)))=(T_(1))/(T_(2))`
`rArr` Temperature of the gas `T_(2)=T_(1)sqrt((V_(2))/(V_(1)))=Tsqrt((2V)/(V))=sqrt(2T)`