The gas in a vessel is subjected to a pressure of `20` atmosphere at a temperature `27^(@)C`. The pressure of the gas in the vessel after one half of the gas is released from the vessel and the temperature of the remainder is raised by `50^(@)C` is

Options

A. 8.5 atm
B. 10.8 atm
C. 11.7 atm
D. 17 atm

Answer

C

Explanation

Apply `pV=muRT=(m)/(M)RT`
`20xxV=(m)/(M)xxRxx300` ……(i)
`p'xxV=((m/2)/(M))Rxx350` (ii)
From Eqs. (i) and (ii) , we get `p'=(140)/(12)~~11.7atm`