A real gas behaves like an ideal gas if its

Options

A. Phase transition
B. temperature
C. pressure
D. None of these

Answer

C

Explanation

No attractive or repulsive force acts between gas molecules in an ideal gases. Molecules do not exert that force on the wall which they would have exerted in the absence of intermolecular force. Therefore, the observed pressure P of the gas will be less than that present in the absence of the gas will be less than that present in the absence of intermolecular force. Hence, the attractive
becomes `(p+(a)/(V_(2)))`