A balloon contains `500m^(3)` of He at `27^(@)C` and 1 atm pressure. Then , the volume of He at `-3^(@)C` and 0.5 atm pressure will be

Options

A. `700m^(3)`
B. `900m^(3)`
C. `1000m^(3)`
D. `500m^(3)`

Answer

B

Explanation

Using standard gas equation,
`(p_(1)V_(1))/(T_(1))=(p_(2)V_(2))/(T_(2))orV_(2)=(p_(1)V_(1)T_(2))/(p_(2)T_(1))`
`therefore ` Volume fo the `V_(2)=(1xx500xx(273-3))/(0.5xx(273+27))`
`(1xx500xx270)/(0.5xx300)=900m^(3)`