Temperature remaining constant, the pressure of gas is decreased by 20%. The percentage change in volume

Options

A. increases by 29 %
B. decreases by 20%
C. increases by 25%
D. deceases by 25%

Answer

C

Explanation

According to Boyle's law
`p_(1)V_(1)=p_(2)V_(2)`
As the pressure is decreased by 20% , therefore
`p_(2)=(80)/(100)p_(1)=and p_(1)V_(1)=(80)/(100)=p_(1)V_(2)rArrV_(1)=(80)/(100)V_(2)`
`therefore` Percentage increase in volume =`(V_(2)-V_(1))/(V_(1))xx100`
`=(100-80)/(80)xx100=25%`