The temperature at which the mean KE of the molecules of gas is one - third of the mean KE of its molecules at `180^(@)C` is

Options

A. `-122^(@)C`
B. `-90^(@)C`
C. `60^(@)C`
D. `-151^(@)C`

Answer

D

Explanation

Kinetic energy of a gas is directly proportional to its temperature.
`therefore " " (K_(1))/(K_(2))=(T_(1))/(T_(2))`
`rArr " " (K)/(K//3)=(273+180)/(T_(2))`
`rArr " " 3=(453)/(T_(2))`
`T_(2)=151^(@)C`