If the molecular weight of two gases are `M_(1)` and `M_(2)` then at a temperature the ratio of rms velocity `C_(1) and C_(2)` will be

Options

A. `(M_(1)/M_(2))^(1//2)`
B. `(M_(2)/M_(1))^(1//2)`
C. `((M_(1)-M_(2))/(M_(1)+M_(2)))^(1//2)`
D. `((M_(1)+M_(2))/(M_(1)-M_(2)))^(1//2)`

Answer

B

Explanation

As `(1)/(2)Mc^(2)=(3)/(2)RT" or " c=((3RT)/(M))^(1//2)rArrcprop(1)/(sqrtM)`
`"So"," " (c_(1))/(c_(2))=(M_(2)/(M_(1)))^(1//2)`