10 moles of an ideal monoatomic gas at 1...

10 moles of an ideal monoatomic gas at `10^(@)C` are mixed with 20 moles of another monoatomic gas at `20^(@)C`. Then the temp. of the mixture is

A

`15.5^(@)C`

B

`15^(@)C`

C

`16^(@)C`

D

`16.6^(@)C`

Text Solution

Verified by Experts

The correct Answer is:

D

Temperature of the mixture is given by
`T=(n_(1)m_(1)+n_(2)m_(2))/(n_(1)+n_(2))rArrT(10xx10=20xx20)/(10+20)=(500)/(30)`
`~~16.6^(@)C`

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