The speed of sound in hydrogen is `1270 ms^(-1)` at temperature T. the speed at the same T in a mixture of oxygen and hydrogen mixed in a volume ratio 1:4 will be ?

Options

A. `317"ms"^(-1)`
B. `635"ms"^(-1)`
C. `830"ms"^(-1)`
D. `950"ms"^(-1)`

Answer

B

Explanation

As given , the volumes of hydrogen and oxygen in a mixture is `4:1` , so let V be the volume of oxygen . The volume of hydrogen will be 4 V .If `rho_(m)` be the density of mixture, then
`rho_(m)=(4Vxx1+Vxx16)/(5V)=4`
`As " " vprop((1)/(rho))^(1//2)`
`therefore"Velocity in mixture"=(1270)/((4)^(1//2))=635ms^(-1)`