At what temperarture, the kinetic energy of a gas molecule is half of the value at `27^(@)C.` ?

Options

A. `13.5^(@)C`
B. `150^(@)C`
C. `75 K`
D. `-123^(@)C`

Answer

D

Explanation

Kintic energy of a gas molecule, `E=(3)/(2)kT`
where , k is Boltzmann's constant .
`therefore " " EpropT`
`"or"" " (E_(1))/(E_(2))=(T_(1))/(T_(2))rArr(E)/((E//2))=(300)/(T_(2))`
or Temperature `T_(2)=150K=150-273=-123^(@)C`