At ordinary temperatures, the molecules of an ideal gas have only translational and rotational kinetic energies. At high temperatures they may also have vibrational energy.
As a result of this, at higher temperature

Options

A. `C_(v)=(3)/(2)R` for a monoatomic gas
B. `C_(v)gt(3)/(2)R` for a monoatomic gas
C. `C_(v)lt(3)/(2)R` for a diatomic gas
D. `C_(v)=(5)/(2)R` for a diatomic gas

Answer

A

Explanation

At ordinary temperature , the vibratinal kinetic energy of a monoatomic gas is zero .
`"So"" " C_(v)=(3)/(2)R`
The value is same for high temperature also .In caseof diatomic gas
` C_(v)=(5)/(2)R` (at low temperature)
` "Also"" "C_(v)=(5)/(2)R`
(at high temperature due to vibratinal kinetic energy)