Five moles of hydrogen `(gamma = 7//5)`, initially at `STP`, is compressed adiabatically so that its temperature becomes `400^(@)C`. The increase in the internal energy of the gas in kilojules is `(R = 8.30 J//mol-K)`

Options

A. 21.55
B. 41.55
C. 65.55
D. 50.55

Answer

B

Explanation

Here , `n=5,gamma=(7)/(5),T_(1)=0^(@)C,T_(2)=400^(@)C`
`therefore` The internal energy of gas `dU=(nRdT)/(((7)/(5)-1))`
= `(5xx8.31xx(400-0))/(((7)/(5)-1))=41550 J =41.55 KJ`