The temperature of sink of Carnot engine is `27^(@)C`. Efficiency of engine is `25%`. Then temeperature of source is

Options

A. `227^(@)C`
B. `27^(@)C`
C. `327^(@)C`
D. `127^(@)C`

Answer

D

Explanation

Efficiency of cannot engine `eta=1-(T_(2))/(T_(1))` and
`(25)/(100)=1-(300)/(T_(1))`
`(300)/(T_(1))=1-(25)/(100)=(100-25)/(100)=(75)/(100)`
`T_(1)=(300xx100)/(75)=400=400-273=127^(@)C`