A carnot engine operates with source at `127^(@)C` and sink at `27^(@)C`. If the source supplies `40kJ` of heat energy. The work done by the engine is

Options

A. 30 kJ
B. 10 kJ
C. 4 kJ
D. 1 kJ

Answer

B

Explanation

Efficiency ,`eta=1-(T_(2))/(T_(1))`
`eta=1((273+27))/((273+127))=1-(300)/(400)=(1)/(4)`
`eta=("Work done")/("Heat supplied")`
`(1)/(4)=(W)/(40)rArrW=10kJ`