Solar radiation emitted by sun resembles that emitted by a body at a temperature of `6000 K` Maximum intensity is emitted at a wavelength of about `4800A^(@)` If the sun was cooled down from `6000K` to `3000K` then the peak intensity would occure at a wavelenght of .

Options

A. `4800Å`
B. `9600Å`
C. `2400Å`
D. `19200Å`

Answer

B

Explanation

Here , `T_(1)=6000K,lamda_(1)=4800 Å,T_(2)=3000K,lamda_(2)` =?
According to Wien's law ,
` therefore " " (lamda_(2))/(lamda_(1))=(T_(1))/(T_(2))rArrlamda_(2)=(T_(1))/(T_(2))xxlamda_(1)=(6000)/(3000)xx4800=9600Å`