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The temperature of a black body is incre...

The temperature of a black body is increased by 50% , then the percentage of increases of radiation is approximetaly

A

`100%`

B

`25%`

C

`400 %`

D

`500 %`

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The correct Answer is:
To solve the problem, we need to determine the percentage increase in radiation when the temperature of a black body is increased by 50%. We will use Stefan's Law, which states that the energy radiated by a black body is proportional to the fourth power of its absolute temperature. ### Step-by-Step Solution: 1. **Define Initial Temperature**: Let the initial temperature \( T_1 \) be represented as 100% (or simply \( T_1 \)). 2. **Calculate New Temperature**: If the temperature is increased by 50%, the new temperature \( T_2 \) can be calculated as: \[ T_2 = T_1 + 0.5 \times T_1 = 1.5 \times T_1 \] Thus, \( T_2 = \frac{3}{2} T_1 \). 3. **Apply Stefan's Law**: According to Stefan's Law, the energy radiated \( E \) is proportional to \( T^4 \): \[ E \propto T^4 \] Therefore, the ratio of the energies at the two temperatures can be expressed as: \[ \frac{E_2}{E_1} = \left(\frac{T_2}{T_1}\right)^4 \] Substituting \( T_2 = \frac{3}{2} T_1 \): \[ \frac{E_2}{E_1} = \left(\frac{3/2}{1}\right)^4 = \left(\frac{3}{2}\right)^4 = \frac{81}{16} \] 4. **Calculate the Increase in Radiation**: To find the percentage increase in radiation, we use the formula: \[ \text{Percentage Increase} = \frac{E_2 - E_1}{E_1} \times 100 \] Substituting \( E_2 = \frac{81}{16} E_1 \): \[ \text{Percentage Increase} = \frac{\frac{81}{16} E_1 - E_1}{E_1} \times 100 = \left(\frac{81}{16} - 1\right) \times 100 \] Simplifying: \[ = \left(\frac{81 - 16}{16}\right) \times 100 = \frac{65}{16} \times 100 \] 5. **Final Calculation**: Now, calculate \( \frac{65}{16} \): \[ \frac{65}{16} = 4.0625 \] Therefore, the percentage increase in radiation is approximately: \[ 4.0625 \times 100 = 406.25\% \] Rounding off, we find that the percentage increase in radiation is approximately **400%**. ### Conclusion: The percentage increase in radiation when the temperature of a black body is increased by 50% is approximately **400%**.

To solve the problem, we need to determine the percentage increase in radiation when the temperature of a black body is increased by 50%. We will use Stefan's Law, which states that the energy radiated by a black body is proportional to the fourth power of its absolute temperature. ### Step-by-Step Solution: 1. **Define Initial Temperature**: Let the initial temperature \( T_1 \) be represented as 100% (or simply \( T_1 \)). 2. **Calculate New Temperature**: ...
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-KINETIC THEORY OF GASES ANDRADIATION-Exercise 1
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  2. When a gas filled in a closed vessel is heated through 1^(@)C, its pre...

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  3. An inflated rubber balloon contains one mole of an ideal gas has a pre...

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  4. The total radiant energy per unit area, normal to the direction of inc...

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  5. At 273^(@)C ,the emissive power of a perfect black body is R . What ...

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  6. A black body at 227^(@)C radiates heat at the rate of 7 cal cm^(-2) s...

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  7. The rate of emission of a black body at 0^(@)C is its rate of emissio...

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  8. Two spherical black bodies of radii R(1) and R(2) and with surface tem...

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  9. A solid cube and a solid sphere of the same material have equal surfac...

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  10. Two gases A and B having the same temperature T, same pressure P and s...

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  11. The rectangular surface of area 8 cm xx 4 cm of a black body at temper...

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  12. The air density at mount Everest is less than that at the sea level . ...

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  13. The temperature of a black body is increased by 50% , then the percent...

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  14. The frequency (v(m)) corresponding to which energy emitted by a black...

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  15. A kettle with 2 litre water at 27^@C is heated by operating coil heate...

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  16. An object is cooled from 75^(@)C to 65^(@)C in 2 min in a room at 30^(...

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  17. A planet is at an average distance d from the sun and its average surf...

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  18. The power of black body at temperature 200 K is 544 W .Its surface are...

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  19. The wavelength of maximum intensity of radiation emitted by a star is ...

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  20. A body cools from 80^(@)C to 50^(@)C in 5 min-utes Calculate the time ...

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