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The power of black body at temperature 2...

The power of black body at temperature 200 K is 544 W .Its surface area is
`(sigma=5.67xx10^(-8)Wm^(-2)K^(-2))`

A

`6xx10^(-2)m^(2)`

B

`6m^(2)`

C

`6xx10^(-6)m^(2)`

D

`6xx10^(2)m^(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
According to Stefan 's law , `(Q)/("At")=sigmaT^(4)`
`"Here "(Q)/(t)=544,T=200K,`
`sigma=5.67xx10^(-8)Wm^(-2)K^(-4)`
`therefore" " A=(Q)/(sigmatT_(4))=(544)/(5.67xx10^(-8)xx(200)^(4))=6m^(2)`
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