Light waves form two coherent source having intensity ration `81:1` produce interference. Then, the ratio of maxima and minima in the interference pattern will be

Options

A. `(18)/(23)`
B. `(16)/(25)`
C. `(25)/(16)`
D. `(23)/(18)`

Answer

C

Explanation

Given, `(I_(1))/(I_(2))=(A_(1)^(2))/(A_(2)^(2))=(81)/(1)`
`therefore (A_(1))/(A_(2))=(9)/(1) rArr A_(1)=9A_(2) " " ` ...(i)
`therefore (I_("max"))/(I_("min"))=((A_(1)+A_(2))^(2))/((A_(1)-A_(2))^(2))`
From Eq. (i), we get
`(I_("max"))/(I_("min"))=((9A_(2)+A_(2))^(2))/((9A_(2)-A_(2))^(2))=((10)^(2))/((8)^(2))=(25)/(16)`