In Young's double slit experiment interference fringes `1^(@)` apart are produced on the screen, the slit separation is `(lambda = 589 nm)`

Options

A. 0.546 mm
B. 0.0337 mm
C. 0.246 mm
D. 0.0927 mm

Answer

B

Explanation

Given, `theta=1^(@)=(pi)/(180)"rad" rArr lambda=589 nm`
The fringe width, `beta=(lambdaD)/(d)`
The angular separation of the fringes is given by
`theta=(beta)/(D)=(lambda)/(d)`
`therefore` Slit separation `d=(lambda)/(theta)=(589xx180xx10^(-9))/(pi)=0.0337 mm`