Calculate the resolving power of a microscope with cone angle of light falling on the objective equal to `60^(@)`. Take `lambda = 600 nm , mu` for air `= 1`.

Options

A. `1.67xx10^(6)m^(-1)`
B. `1.03xx10^(5)m^(-1)`
C. `0.67xx10^(5)m^(-1)`
D. `8.96xx10^(6)m^(-1)`

Answer

A

Explanation

Given, `2theta=60^(@), theta=30^(@), lambda=600 nm`
`=6xx10^(-7)m, mu=1`
We have, resolving power (RP) of microscope
`=(1)/(d)=(2mu sin theta)/(lambda)`
`therefore RP=(2xx1xx sin 30^(@))/(600xx10^(-9))=(10)/(6)xx10^(6)=1.67xx10^(6)m^(-1)`