A telescope is used to resolve two stars separated by `4.6xx10^(-6)` rad. If the wavelength of light used is `5460 Å` , what should be the aperture of the objective of the telescope ?

Options

A. 0.0448 m
B. 0.1448 m
C. 1.1448
D. 0.011 m

Answer

B

Explanation

Here, `dtheta=4.6xx10^(-6)"rad", lambda=5460"Å"=5460xx10^(-10)m`
The aperture (D) of the telescope is given as,
`D=(1.22lambda)/(d theta) or D=(1.22 xx 5460xx10^(-10))/(4.6xx10^(-16))`
`=0.1448m`