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Two coherent monochormatic light source are located at two vertices of an equilateral trangle. If the intensity due to each of the source independently is `1Wm^(-2)` at the third vertex. The resultant intensity due to both the sources at that point (i.e at the third vertex) is (in `Wm^(-2)` )

A

zero

B

`sqrt(2)`

C

2

D

4

Text Solution

Verified by Experts

The correct Answer is:
D

Intensity `I_(1)=I_(2)=1Wm^(-2)`
So, resultant intensity at third vertex
`I=(sqrt(I_(1))+sqrt(I_(2)))^(2)=(sqrt(1)+sqrt(1))^(2)=(1+1)^(2)=4Wm^(-1)`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-INTERFERENCE AND DIFFRACTION OF LIGHT -Exercise 1 (TOPICAL PROBLEMS)
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  11. In the setup shown in figure, the two slits, S(1) and S(2) are not equ...

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  12. The separation between successive fringes in a double slit arrangement...

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  13. In a Young's double-slit experiment, let S(1) and S(2) be the two slit...

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  14. In the Young's double slit experiment , a mica slip of thickness t and...

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  15. In double slit experiment, the angular width of the fringes is 0.20^@ ...

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  16. A beam of light consisting of two wavelength 650nm and 520nm is used t...

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  17. In Young's double slit experiment, the 8th maximum with wavelength lam...

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  18. In a Young's experiment, two coherent sources are placed 0.90mm apart ...

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  19. The wavelength of the light used in Young's double slit experiment is ...

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