In Young's double slit experiment, the 10th maximum of wavelength `lambda_(1)` is at distance of `y_(1)` from the central maximum. When the wavelength of the source is changed to `lambda_(2)` , 5th maximum is at a distance of `y_(2)` from its central masximum. Then `(y_(1))/(y_(2))` is

Options

A. `(2lambda_(1))/(lambda_(2))`
B. `(2lambda_(2))/(lambda_(1))`
C. `(lambda_(1))/(2lambda_(2))`
D. `(lambda_(2))/(2lambda_(1))`

Answer

A

Explanation

For 10th maxima, `Y_(1)=10beta_(1)=(10lambda_(1)D)/(d)`
For 5th maxima, `Y_(2)=5beta_(2)=(5lambda_(2)D)/(d)`
`therefore (Y_(1))/(Y_(2))=2(lambda_(1))/(lambda_(2))`