In a biprism experiement, by using light of wavelength `5000Å`, `5mm` wide fringes are obtained on a screen `1.0m` away from the coherent sources. The separation between the two coherent sources is

Options

A. 1.0 mm
B. 0.1 mm
C. 0.05 mm
D. 0.01 mm

Answer

B

Explanation

We known that `beta=(lambdaD)/(d)`
`rArr 5 xx10^(-3)=((5000xx10^(-10))xx1.0)/(d)`
The separation between the two coherent sources,
`d=(5xx10^(-7))/(5xx10^(-3))=10^(-4)m=0.1 mm `