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A parallel beam of light of wavelength 6...

A parallel beam of light of wavelength `6000Å` gets diffracted by a single slit of width 0.3 mm. The angular position of the first minima of diffracted light is :

A

`6xx10^(-3)` rad

B

`1.8xx10^(-3)` rad

C

`3xx10^(-3)` rad

D

`2xx10^(-3)` rad

Text Solution

Verified by Experts

The correct Answer is:
D
We have d `sin theta =n lambda`
`0.3xx10^(-3) xx theta=6000xx10^(-10)`
The angular position ` theta=2xx10^(-3)` rad
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-INTERFERENCE AND DIFFRACTION OF LIGHT -Exercise 2 (MISCELLANEOUS PROBLEMS)
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  2. Light of wavelength lamda is incident on a slit of width d. the result...

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  9. In Young's double slit experiment the two slits are d distance apart....

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  10. In a Young's double slit experiment (slit distance d) monochromatic li...

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  11. A parallel beam of light of wavelength 500 nm falls on a narrow slit ...

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  12. A parallel beam of light of wavelength 6000Å gets diffracted by a sing...

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