In a double slit experiment, the two slits are 1 mm apart and the screen is placed 1 m away. A monochromatic lightg of wavelength 500 nm is used, what will be the width of each slit for obtaining ten maxima of double slit within the central maxima of single slit pattern ?

Options

A. 0.2 mm
B. 0.1 mm
C. 0.5 mm
D. 0.02 mm

Answer

A

Explanation

Given, `d=1mm=1xx10^(-3)m`
`D=1m`
`lambda=500nm=5xx10^(-7)m`
As width of central maxima = width of 1o maxima
`therefore (2 D lambda)/(a)=10((lambdaD)/(d))`
`rArr a=(d)/(5)=(10^(-3))/(5)=0.2xx10^(-3)m`
`rArr a=0.2 mm`