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A plane wave front of wavelength lamda i...

A plane wave front of wavelength `lamda` is incident on a single slite of width b. What is the angular width for secondary maximum ?

A

`(lambda)/(2b)`

B

`(lambda)/(b)`

C

`(2lambda)/(b)`

D

`(b)/(lambda)`

Text Solution

Verified by Experts

The correct Answer is:
B

`beta=(lambdaD)/(d) and theta=(beta)/(D)`
`therefore theta=(lambda)/(d)`
`therefore` Width of single slit = b
So, `theta=(lambda)/(b)`
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MHTCET PREVIOUS YEAR PAPERS AND PRACTICE PAPERS-INTERFERENCE AND DIFFRACTION OF LIGHT -MHT CET Corner
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