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In Young's double slit experiment, wavel...

In Young's double slit experiment, wavelength `lambda=5000Å` the distance between, the slits is `0.2mm` and the screen is at 200cm from the slits. The central maximum is at `x=0` The third maximum (Taking the central maximum as zeroth maximum) will be at x equal to

A

5 cm

B

0.5 cm

C

1.67 cm

D

1.5 cm

Text Solution

Verified by Experts

The correct Answer is:
D
Position of maxima is
`y_(n)=(xDlambda)/(d)`
`=(3 xx(2.0)xx(5xx10^(-7)))/(0.2xx10^(-3))`
`=1.5xx10^(-2)m`
`=1.5cm`
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