If the ratio of amplitude of two waves is `4:3`, then the ratio of maximum and minimum intensity is

Options

A. `16:18`
B. `18:16`
C. `49:1`
D. `1:49`

Answer

C

Explanation

In the interference pattern,
`I_("max")=(a+b)^(2)and I_("min")=(a-b)^(2)`
`(I_("max"))/(I_("min"))=((a+b)^(2))/((a-b)^(2))=((4+3)^(2))/((4-3)^(2))`
`((7)/(1))^(2)=(49)/(1)=49:1`